Range Over Channels in Prolog

Our example demonstrates how to iterate over values received from a channel-like structure in Prolog. Since Prolog doesn’t have built-in channels or concurrency primitives like Go, we’ll simulate this behavior using a list and recursive predicates.

% Simulate sending values to a channel
queue(['one', 'two']).

% Predicate to process each element
process(Element) :-
    write(Element), nl.

% Iterate over the queue
iterate_queue([]).
iterate_queue([Head|Tail]) :-
    process(Head),
    iterate_queue(Tail).

% Main predicate
main :-
    queue(Queue),
    iterate_queue(Queue).

In this example, we define a queue/1 fact to simulate a channel with two elements. The process/1 predicate is used to handle each element, which in this case simply prints it.

The iterate_queue/1 predicate is a recursive predicate that processes each element in the list. It’s analogous to the range loop in the original example.

The main/0 predicate ties everything together, retrieving the queue and initiating the iteration.

To run this program:

?- main.
one
two
true.

This example demonstrates how we can simulate iterating over channel-like structures in Prolog using list processing and recursion. While Prolog doesn’t have built-in concurrency features like channels, this approach allows us to process sequences of data in a similar manner.

Note that in Prolog, we don’t need to explicitly close our “channel” (list) as it has a defined end. The recursion naturally terminates when we reach the end of the list.