Timeouts in Prolog
Timeouts are important for programs that connect to external resources or that otherwise need to bound execution time. Implementing timeouts in Prolog can be achieved using built-in predicates and library modules.
:- use_module(library(process)).
:- use_module(library(system)).
main :-
% For our example, suppose we're executing an external
% call that returns its result after 2 seconds.
process_create(path(sleep), ['2'], [process(P1)]),
% Here we implement a timeout using the wait_for_process/3 predicate.
% It waits for the process to finish or for a timeout to occur.
( wait_for_process(P1, exit(_), [timeout(1000)])
-> writeln('result 1')
; writeln('timeout 1'),
process_kill(P1)
),
% If we allow a longer timeout of 3 seconds, then the process
% will complete and we'll print the result.
process_create(path(sleep), ['2'], [process(P2)]),
( wait_for_process(P2, exit(_), [timeout(3000)])
-> writeln('result 2')
; writeln('timeout 2'),
process_kill(P2)
).
:- main.
In this Prolog implementation:
We use the
process
library to create external processes that simulate long-running operations.The
process_create/3
predicate is used to start a process that sleeps for 2 seconds, simulating a time-consuming task.We use
wait_for_process/3
to wait for the process to finish or for a timeout to occur. The timeout is specified in milliseconds.If the process finishes before the timeout, we print the result. Otherwise, we print a timeout message and kill the process.
We demonstrate two scenarios: one with a 1-second timeout (which will fail) and another with a 3-second timeout (which will succeed).
Running this program shows the first operation timing out and the second succeeding:
$ swipl -q -t main timeouts.pl
timeout 1
result 2
This Prolog implementation provides similar functionality to the original Go code, adapting the concepts of goroutines and channels to Prolog’s process handling and timeout mechanisms.